Friday, April 15, 2011

Data Handling (Mean from Frequency Table)

How to calculate Mean from Frequency Table

A. The process
Refer to the following link for information on the process.

B. Notation 



B. Question:
Please post your answer to the following question. Show your working clearly.


source: http://www.mathsisfun.com

22 comments:

  1. Take parking spaces as x
    Take sigma as E
    Take frequency as f

    Efx/Ef=(15x1+27x2+8x3+5x4)/(15+27+8+5)
    =113/55
    =2.05454545454545....

    Rounded off=2.05

    Ans:2.05

    ReplyDelete
  2. 1(15) + 2(27) + 3(8) + 4(5) = 113
    15+27+8+5 = 55
    113÷55= 2.054545454545........

    We round off the answer to 3 sig fig which will give us 2.05

    Ans: 2.05

    ReplyDelete
  3. 1(15) + 2(27) + 3(8) + 4(5) = 113
    113÷the frequency=113÷(15+27+8+5)=113÷2.0545454 and so on with the 5s and 4s. :)
    We will round off the number to 3 significant figures, so the answer is 2.05.

    ReplyDelete
  4. This comment has been removed by the author.

    ReplyDelete
  5. 1(15) + 2(27) + 3(8) + 4(5) / 15+27+8+5
    = 113/55
    =2.0545454545454545454545454545454545454545454545454545454545454545454545454545454545454545........( Maximum Limit Of Intel Core 2 Duo Chips Reached )( P.S. Number is indefinite )

    ≈2.05

    Answer : 2.05

    ReplyDelete
  6. (1x15)+(2x27)+(3x8)+(4x5)=113
    15+27+8+5=55

    113/55~~2.05

    Answer = 205

    ReplyDelete
  7. ∑ƒx 1(15) + 2(27) + 3(8) + 4(5)
    mean = ---- = mean = ---------------------------
    ∑ƒ 15 + 27 + 8 + 5

    ≈2.05

    ReplyDelete
  8. Let the: 1) Number of Parking Spaces be x
    2) Number of frequency be f

    ∑fx: 1(15)+2(27)+3(8)+4(5)=113
    ∑f: 15+27+8+5=55

    Mean number: 113÷55≈2.054 ( 4 Significant Figures )
    ≈2.05 ( 3 Significant Figures )

    ReplyDelete
  9. 1st: Find the sum of the parking spaces multiplied by the frequency

    (1 x 15) + (2 x 27) + (3 x 8) + (4 x 5) = 113

    2nd: Find the sum of the frequency-

    15 + 27 + 8 + 5=55

    3rd: Find the mean by dividing the sum of the parking spaces multiplied by the frequency and the frequency itself.

    113 / 55 = 2.05 (3 SigFig)

    Ans = 2.05

    ReplyDelete
  10. (1x15=15)+(2x27=54)+(3x8=24)=(4x5=20)=113
    15+27+8+5 = 55
    113÷55= 2.054545454545.....≈2.05

    ReplyDelete
  11. (1x15)+(2x27)+(8x3)+(4x5)=113
    15+27+8+5=55
    113÷55=2.054(4SF)2.05(3SF)

    Answer: 2.05

    ReplyDelete
  12. 1(15) + 2(27) + 3(8) + 4(5) = 113
    15+27+8+5 = 55
    113÷55= 2.054545454545........

    Round off to 3 sig. fig. = 2.05

    ReplyDelete
  13. 1(15)+2(27)+3(8)+4(5)=113
    15+27+8+5=55

    113/55=2.05454.............

    So you round it if 3 significant figure which is=2.05

    ReplyDelete
  14. ∑ƒx/∑ƒ
    15(1)+27(2)+8(3)+5(4)/15+27+8+5
    =113/55≈2.05

    ReplyDelete
  15. ∑ƒx/∑ƒ = 15(1)+27(2)+8(3)+5(4)/15+27+8+5 = 2.054545454.....≈2.05 (rounded to 3 sig. figures)

    Mean number of parking spaces: 2.05

    ReplyDelete
  16. 1x15+2x27+3x8+5x4=15+27+8+5=2.0545454545......=2.05

    ReplyDelete
  17. 1(15) + 2(27) + 3(8) + 4(5)=113
    113/15+27+8+5≈2.05

    ReplyDelete
  18. 15x1+27x2+8x3+5x4=113(frequency times score)
    15+27+8+5=55(total frequency)
    113/55 (round of to 3 sig. fig.) is 2.05

    ReplyDelete
  19. @Ragul:
    You dun need to continue putting those numbers in, just round it off.

    ReplyDelete
  20. 1(15)+2(27)+3(8)+4(5)=113
    15+27+8+5=55
    113÷55≈2.05
    Ans:2.05

    ReplyDelete
  21. (1x15) + (2x27) + (3x8) + (4x5) = 113
    15 + 27 + 8 + 5 = 55
    113 divided by55≈2.05 (When rounded of to 3 significant figures)

    ReplyDelete
  22. 1(15) + 2(27) + 3(8) + 4(5) = 113
    15 + 27 + 8 + 5 = 55
    113/55 = 2.05 (rounded off to 3 sig. figures)

    The mean number of parking spaces is 2.05.

    ReplyDelete